Last year, in another thread I devised a mathematical formula for how many kilts a man should own...

Let P = # of pairs of pants owned
Let x = days per week pants are worn
Let t = time of 1 rotation cycle in days (e.g. 365 days)

dp = days spent wearing pants per cycle rotation
dk = days spent wearing kilts per cycle rotation

k = theoretical number of kilts that should be owned for optimal wear

(1a) x/7*t=dp ; (1b) [(7-x)/7]*t=dk

(2) k = dk*(p/dp)

Solve for k.

Theoretical example.

I own 15 pairs of pants that I wear 5 days a week (Mon - Fri) for work. Then I walk around kilted on the weekends. I'm working on a 1 year rotation cycle.

P=15
x=5
t=365

(1a) (5/7)*365=261 dp=261 : (1b) (2/7)*365=104 dk=104

(2) (15/261)*104 = 6

Therfore, I should have 6 kilts in my wardrobe for kicking around on weekends.